-0.2x^2+0.1x=0.04

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Solution for -0.2x^2+0.1x=0.04 equation: 



-0.2x^2+0.1x=0.04

We move all terms to the left:

-0.2x^2+0.1x-(0.04)=0

We add all the numbers together, and all the variables

-0.2x^2+0.1x-0.04=0

a = -0.2; b = 0.1; c = -0.04;
Δ = b2-4ac
Δ = 0.12-4·(-0.2)·(-0.04)
Δ = -0.022
Delta is less than zero, so there is no solution for the equation

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